Number elimination

[Frank]

(07-27-2009 12:19 AM)ido Wrote:  Hi,Frank,not too sure if i understand well your theory ,but it seem to me you'l have very interesting results if make 2 separate ,indipendent lists of eliminated even numbers& eliminated odd numbers- if do like this you'l notice periodicaly(and short intervals from period to period) near full cover - second me have often Pick's3 won is not bad......or punt separately the odds &the evens of the both :elimination list and bankers list.

Hi Ido, my theory is based on the statistic that a number from a past draw has roughly a 50:50 chance of apearing in the next draw to come. The problem is that there have been a lot of past draws. As it stands, therefore any number can appear in the next draw. However , by observing which draws repeat to other draws most consistently you find out those which temporarily at least are bucking the trend, and are repeating with 100% certainty. Thats why I'm looking at the last 14 draws and finding out which consecutive draws in the past repeated to them without missing any draws. So this is a trend, it won't go on forever but it might just do one more repeat - which is all we are interested in. See the attached image.
Between draws 1405 and 1417 there was an unbroken run of repeated numbers from draws 20 draws earlier, So in draw 1417, number 31 repeated from draw 1397 , in draw 1416 numbers 9 and 28 repeated from draw 1396 etc. In other words draws 1385 to 1397 consecutively had results which reappeared 20 draws later. This unbroken run only came to an end in the last draw 1418 where draw 1398 failed to repeat.

Unbroken runs of this length are very rare and I'm now dealing with broken runs of 14 draws with just a single break in them such as repeats from draws 961 draws ago ( skip=961) to the last 14 draws ! Having identified a skip value of interest, all I need to look at is what the result was (in this example ) 961 draws ago to get 6 possible balls for the next draw. There are other skip values of interest too giving more balls in the list.
I look at a consensus for all the balls in the repeating group(s) to look for the most prolific (bankers list) and the absent balls (elimination list).
I don't want to complicate this method any more by messing about with odds and evens , I've been there and done all that with various systems over the years, so for the time being I'll stick to fine tuning this method, to see if I can get consistent results.
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