Number elimination

[Frank]

(08-04-2009 07:33 PM)Len Wrote:  Hi Frank
Look at the numbers in the top two draws.
and the result of the last two draws.

Wed 25/03/2009 1383: 13,23,26,27,37,49 BB 47
Sat 28/03/2009 1384: 02,17,19,28,31,47 BB 14

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The last two draw results
Wed 29/07/2009 1419: 03,13,19,20,23,26 BB 01
Sat 01/08/2009 1420: 02,06,27,28,40,49 BB 14

From the two top draws they got numbers.
13,19,23,26
02,27,28,49 BB 14

Numbers over from the above list are 17,31,37,47
you never know?

Phew, thank goodness for that, I thought I was going mad. Thats what happens when you go off topic and mix methods. The word 'they' confused me (I thought you meant Ido).

Basically, back on topic - you've spotted a good skip value, of 36 which means 1383 and 1384 had good repeats to 1419 and 1420.

It could be we are well into a good run with that one, as its done 5 consecutive repeats from draw 1379 to 1384 so far. As you say those two draws eliminate a set provided the repeat run continues. its a skip to keep an eye on.
I'm currently working with sets of 10 draws derived in the same way to create my lists, currently Im not using 36 simply because other skips have longer consecutive runs at the moment, but soon will if it continues.

Edit :- youve just given me an idea. Its not the longest consecutive runs (of repeats) which are likely to continue, its the ( median value minus 1) of the length of all the runs ! The median value is 6 , so consecutive runs of 5 are most likely to become runs of 6. Len you are a Genius. Back to the drawing board !